Choosing Sides


“No one cannot slave for two masters; for either he will hate the one and love the other, or he will stick to the one and despise the other.” – Matthew 6:24

Religion is a hotly discussed topic nowadays, just as it always has been, and there probably isn’t anyone who doesn’t have an opinion on it. It’s also probably fair to say that most of these opinions are far from magnanimous- cue Choosing Sides. Rather than portraying faith as a drab and dreary subject of contention, this neat little short shows the funny side of religious conflict.
An 11 year old child is lectured by his arguing parents on which religion he should belong to. In the red corner; his Catholic father, and in the blue corner; his Jewish mother. A seemingly inconspicuous conversation about the kid’s upcoming birthday turns into a gladiatorial match of Catholics vs. Jews, with the poor little child stuck in the middle.

As mentioned, religion could easily become a fairly mundane subject, yet writer Yael Green manages to make it genuinely funny. Using the conventional put-downs and stereotypes, Green uses the mother and father to create a snappy argument, with a slick style, and clear and clever stichomythia. The dialogue is brilliant in its simple and subtle nature, resulting in a constant stream of funny quips.

Rachel Lynn Jackson plays the unnamed mother, whose Jewish roots impel her to urge her child to her religion. On the other hand, Timothy J. Cox immediately counters her argument with a short advert to his child about the benefits of Catholicism. Stuck in the middle, Max Plush plays a brilliant child who does eventually makes up his mind, with hilarious consequences.

Although Matthew 6:24 states you cannot slave for two masters, the child in the middle of this movie starts to wonder if he wants to serve either. Choosing Sides is a neat little short that delves into a comedic subject that touches upon a potentially explosive subject, but keeps things clever, unique, but most of all, funny.


About Author

Leave A Reply

two × 1 =